INTRODUCTION:
This web page describes an apparatus for concentrating the TRU in used
nuclear power reactor fuel about 10X by extracting nearly pure UO2
from used fuel. This apparatus uses a closed recrystalization process
to separate the used nuclear fuel bundle atoms into three molecular
groups: pure UO2, Zr and everything else (UO2, TRU oxides, fission
products).
THE FUEL PORTIONS:
The economic strategy is to minimize the used fuel
reprocessing, shipping and storage costs by performing
relatively simple preliminary operations on each power reactor site. These preliminary
operations include:
a) Chopping up the used fuel;
b) Prebaking the chopped fuel to reject vapors and gases (Cs oxides + Kr + Ar +
Xe);
c) Harvesting the used Zr hulls;
d) Dividing the remaining used fuel atoms into one large minimally radioactive UO2 portion
(90%) and one smaller highly radioactive portion (UO2 + FP + TRU).
TRU DEFINITION:
TRU is an acronym for TRans Uranium actinides, atoms with atomic numbers greater than 92 that are formed when the
abundant uranium isotope U-238 is exposed to a thermal neutron flux.
Typically in used CANDU reactor fuel about (1 / 2) of the TRU is Pu-239 and about (1 / 6) of the
TRU is Pu-240.
TRU CONCENTRATION:
TRU concentration is a physical process that
selectively extracts uranium oxide from used CANDU reactor fuel,
resulting in about a 10 fold increase in the TRU fraction in the
remaining residue. The TRU concentration process is of fundamental
economic importance in economic production of fuel for Fast Neutron Reactors
(FNRs).
MOTIVATION:
The
motive for TRU Concentration is to mimimize the overall cost of
producing initial FNR core fuel. This cost reduction is achieved by a
reducing by 10 fold the used reactor fuel mass flow through the
subsequent pyroprocess. This mass flow reduction realized by
selective uranium oxide extraction which:
1) Increases the TRU/U
ratio in the fuel concentrates as required for economic production of
FNR core fuel;
2) Minimizes the mass of CANDU fuel concentrates
that must be transported to a remote fuel reprocessing site;
3)
Reduces the gamma emission from the extracted uranium oxide
sufficiently to make that uranium oxide more economic to transport
and store for future use as the main component of FNR blanket
fuel.
4) Enables complete disposal of TRU from used water cooled
reactor fuel, thus eliminating the necessity of DGRs for nuclear fuel
waste disposal.
APPLICATION:
This used reactor fuel concentration process is of interest to parties
that:
1) Have an inventory of used CANDU reactor fuel and who
would like to use that used fuel to make FNR fuel;
2) Have an inventory of used nuclear fuel from water cooled reactors and who
would like to mitigate the costs of transporting, storing and/or
reprocessing of that used fuel;
3) Have an inventory of used
nuclear fuel from water cooled reactors and who would like to rapidly
convert that used fuel into stable elements that pose no risk to
future human generations;
4) Seek to prevent nuclear weapon
proliferation or further nuclear waste formation via use of closed
system electrolytic fuel reprocessing but who want to minimize the
overall cost.
OVERVIEW:
About 2010 Peter Ottensmeyer realized that there is a way of converting
used CANDU reactor fuel into FNR fuel with no spurious waste streams.
The method, termed the Ottensmeyer Plan, has two major steps. The
first major step involves cutting up the CANDU fuel to expose the UO2
pellet material and then baking the chopped up used fuel at 650 deg C in a
vacuum oven to drive off Cs, other volitles and the inert gas fission
products (FP) which must be captured.
The vacuum baking is followed by molecular component separation using a uranyl nitrate hexahydrate
recrystallization cascade which divides the remaining used CANDU fuel
into three portions:
a) zirconium hulls;
b) 90% of the pellet
weight which is nearly pure uranium oxide;
c) 10% of the pellet weight which is residue containing UO2, FP and TRU.
In the dissolver upstream of the recrystallization cascade the irradiated zirconium hulls are captured in a basket for later use in FNR metallic fuel alloy.
The main reason for prebaking the uranium oxide is to exclude Cs-137 and inert gases from the recrystallization cascade.
For public safety reasons the resulting fuel concentrates should then be transported in shielded containers to a shared remote fuel pyroprocessing site.
Pyroprocessing involves electrolytic molten salt reprocessing of the residue to reduce the oxides to metals, to separate FNR core fuel components, to send fission products to 300 year isolated safe dry storage for natural decay and to fabricate suitably alloyed FNR fuel rods.
The fission
products are not waste. The fission products include rare earths that
are in high demand in the electrical industry. After 300 years in
storage the fission products will need further chemical processing to
extract the valuable elements. Most of this web page focuses on
practical implementation of the recrystalization cascade.
The
Cs isotope Cs-137 is strongly radioactive and should be trapped
during the prebaking and sent to 300 year storage. Also released
during prebaking are the inert gases krypton, xenon and argon that
were trapped within the used nuclear fuel. Since some of the inert
gas isotopes are radioactive these inert gases must be safely
captured and vented far from a metropolis.
These gases can be
caught in an atmospheric pressure cold trap cooled by liquid
nitrogen. The relevant boiling points are:
GAS |
BOILING POINT |
---|---|
Ar |
87.3 K |
Kr |
119.1 K |
Xe |
165.1 K |
CO2 |
194.7 K sublimation |
O2 |
90.2 K |
N2 |
77.3 K |
The neutron activated zirconium hulls were originally used in a CANDU reactor for enclosing the uranium oxide pellets used to fabricate CANDU reactor fuel bundles. This irradiated zirconium can be used in the FNR metallic fuel alloys to prevent the plutonium fraction of FNR core fuel from forming a low melting point Pu-Fe eutectic with the Fe fraction of the fuel tube alloy.
The largest residue portion, which comprises about 90% of the used nuclear fuel weight, consists of nearly pure uranium oxide. The ratios of the uranium isotopes in this portion are determined by the neutron irradiation history of the nuclear fuel. For used CANDU fuel this portion has a very low radioactivity permitting relatively easy and inexpensive handling, transportation, storage and reprocessing with minimal gamma ray shielding requirements. Nearly pure UO2 extracted from used CANDU fuel has a low radioactivity whereas UO2 extracted from used Light Water Reactor (LWR) fuel has a higher radioactivity due to the presence of a larger fraction of U-232. The required amount of UO2 shielding is set by the U-232, U-235 and Np-237 concentrations in the uranium oxide as well as impurities. These uranium isotopes may be present at low concentrations in the nearly pure UO2.
The smaller
portion (10%) contains the balance of the used nuclear fuel weight.
For used CANDU fuel this portion is typically: oxides of U, TRU and
fission products. This portion is intensely radioactive and must be
handled and shipped in suitable shielded shipping containers that
have walls that have a gamma ray absorption thickness the equivalent
of a 30 cm thickness of lead and must be stored in dry shielded
containers or vaults. The cost of transporting this portion is
dominated by the cost of transporting the weight of the required
shielded shipping containers. A major safety concern with respect to
this portion is ensuring that the used fuel will not go critical if
water penetrates the used fuel container.
THE U-232 ISSUE:
One of the radioisotopes of concern is U-232 which can
potentially occur in used CANDU fuel as a result of alpha particle
capture and 4 n emission by impurity Th-232 atoms. Being an isotope
of uranium it is not removed by the uranium selective
recrystalization methodology used in this process. The U-232 has a
half life of 72 years and its decay path involves a hard gamma
emission. Since the Th-232 impurity content in the uranium used to
produce CANDU fuel can potentially vary it may be necessary to
measure the gamma ray output from the separated uranium oxide and to
provide sufficient shielding to ensure safety compliance (Ref: Monica
Regalbuto, monica.regalbuto@inl.gov, Purex expert at INL).
THE NEPTUNIUM ISSUE:
For chemical reasons the neptunium is not
excluded from UO2 during the uranyl nitrate hexahydrate
recrystallization process.
REFERENCES:
For an overview of the Ottensmeyer Plan please review OTTENSMEYER
PLAN.
For an
overview of nuclear fuel waste processing see the paper:
Radioactive
Waste Partitioning and Transmutation.
Reference:Â Japanese
2002 patent
For an
overview of Uranyl nitrate hexahydrate [UO2(NO3)2.6H2O] solubility
see:Â Uranyl Nitrate
Solubility
and
Uranyl nitrate
hexahydrate solubility in nitric acid and its crystallization
selectivity in the presence of nitrate salts
and
Uranyl
nitrate hexahydrate solubility
A paper on decontamination factors actually realized is:Â Enhancement of Decontamination Performance of Impurities for Uranyl Nitrate Hexahydrate
A paper
relevant to the U-232 issue is:Â
Uranium-232 Production In Current Design LWRs
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FUEL
CONCENTRATION OPERATIONAL OBJECTIVE:
Selective extraction of
uranium oxide should be done at existing CANDU reactor sites to
realize about 90% of the spent CANDU fuel weight as nearly pure
uranium oxide and the remaining 10% consisting of: (about 2.45% of
spent CANDU fuel weight as a mixture of fission products + TRUs) +
(remaining 7.55% of the CANDU fuel weight is uranium oxide). The
uranium content of this mixture is used to meet the uranium metal
content requirement of the FNR fuel. The extracted nearly pure
uranium oxide must be sufficiently pure to reduce its radioactivity
sufficiently to enable low cost transportation and storage.
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The operations
that need to be performed at each major power reactor site
include:
a) Chopping up the CANDU fuel bundles;
b) Prebaking
the chopped pieces in a vacuum furnace to capture Cs, other volitiles
and inert gases;
c) Dissolving the residue in nitric acid to make
a warm saturated uranium nitrate hexahydrate [UO2(NO3)2.6H2O]
solution;
d) Separating pure uranium nitrate hexahydrate from
other substances using a 7 stage recrystallization cascade;
e)
Nitric acid recovery leaving a 90% pure UO2 pile and a 10% residue
pile.
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UO2(NO3)2
SOLUBIlITY IN NITRIC ACID:
0 deg C = 98 g / 100 g H2O
20
deg C = 122 g / 100 g H2O
100 deg C = 474 g / 100 g H2O
The imporance
of this data is that when a saturated uranyl nitrate hexahydrate
solution at 100 deg C is cooled to 20 degree C the weight of crystals
formed per 100 g H2O will be:
474 g - 122 g = 352 g
The initial
solution weight
474 g + 100 g = 574 g
Thus more than 50% of
the initial warm solution weight forms crystals.
Note that there is little merit in further increasing the weight fraction of crystals because, while in theory that reduces the requred number of stages, it sacrifices crystal face washing by the remaining liquid solution.
Email from
Peter:
Off the top of my head uranium nitrate hexahydrate
dissolves in water up to about 66 %, i.e. it is not solid UNH but
diluted with the 34% water. When it crystallizes out it has a density
as a solid of about 2.8 g/cc whereas the density of the solution is
roughly
2.8 x .66 + 1.0 x .34 or about 2.2.
Therefore I expect
the crystals that form spontaneously to sink.
However, if a cold
surface is introduced into the hot solution, then I would expect the
crystals to form on the cold surface and stick there (depending on
the properties of that surface) until they are scraped off.
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RECRYSTALLIZATION
PURIFICATION OPERATING PRINCIPLE:
The dissolver temperature is
kept at 100 degrees C, the dissolver solution is saturated by
maintaining an excess of used CANDU fuel in the dissolver tank.
Assume that a
measured amount of solution from the dissolver tank is transferred
into Tank T1a.
Assume that we start with tank T1a holding a
uniform warm saturated liquid HNO3 solution that contains multiple
solutes. Assume that one solute So (uranyl nitrate hexahydrate) is
dominant. The other non-dominant solutes are S1, S2, etc. From the
perspective of the dominant solute So the fraction of each impurity
Sn is:
(Sn / So).
If the solution is gradually cooled it will
form dominant solute crystals surrounded by liquid solution
containing the lesser solutes. We need the dominant solute crystal
formation rate to be sufficiently small that the resulting dominant
solute crystals are sufficiently large that their discharge from the
tank can be mostly prevented by use of a simple grating or course
filter. Now drain off the cool liquid solution portion in Tank T1a to
Tank T1b. Use a course filter on the cool solution drain line to
prevent the crystals flowing out the drain.
The crystals
are highly regular atomic structures. During dominant solute crystal
formation within a saturated liquid solution mamy of the impurities
tend to be excluded from the dominant solute crystal and hence will
accumulate in the surrounding liquid and on the crystal faces. It is
important to maintain solution agitation sufficient to continuously
wash the impurities off the crystal faces.. If, after dominant solute
crystal formation, the surrounding liquid is drained off the excluded
impurity concentration in this drained off liquid is about:
(Sn /
Sob)
where Sob is the portion of So in the drained off liquid and
the excluded impurity concentration in the crystals is close to zero.
Now assume
that it is physically practical to make the weight of dominant solute
crystals about equal to the weight of drained off liquid. Then:
Sob
~ (So / 2)
The impurity
concentration in the drained off liquid is:
[Sn / Sob]
= (Sn /
So)(So / Sob)
~ 2 (Sn / So)
Now warm up the crystals remaining in tank T1a. They are nearly pure with respect to exclusion of impurity Sn. Drain out this liquid to another tank T2a via a micron filter. This filtrate is very pure. The purpose of the micron filter is to try to trap in the tank T1a impurities that were incorporated into the solid crystal but not chemically bound. These impurities will tend to drain out to tank T1b via the course filter at the next opportunity.
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A detailed
description of the design and operation of the Uranyl Nitrate
Hexahydrate automatic crystal growing chamber is set out at:
Uranyl
Nitrate Hexahydrate Crystal Growth
RECRYSTALLIZATION
PROCESS CONSTRAINTS:
1) The process equipment must not be so
large that a critical mass can accumulate anywhere in the apparatus.
We must be careful in tank T1b where the impurity concentration is
highest.
2) Nitric acid (4.5 M) acting on uranium oxide produces
uranyl nitrate hexahydrate. The process of recrystalization of uranyl
nitrate hexahydrate [UO2(NO3)2.6H2O] is used to selectively extract
nearly pure UO2 from spent CANDU fuel. This process is ineffective at
rejecting the elements Np and Cs. The Np simply stays mixed with the
uranium. It is not a radioactivity problem unless it contains the
isotope Np-237. Np-237 arises from fast neutron n > 2n reactions
in U-238. In CANDU reactors the fast neutron flux is very low, so the
Np-237 production is low so the contribution of Np-237 to spent fuel
radioactivity is very low. This statement is not true for spent fuel
from fast neutron reactors. Hence recrystalization of
[UO2(NO3)2.6H2O] will not achieve comparable radioactivity reduction
in spent fuel from fast neutron reactors.
3) The process of
recrystalization of [UO2(NO3)2.6H2O] is also ineffective at rejection
of CsNO3.2H2O from the crystals. Before the recrystalization steps Cs
is rejected by heating the uranium oxide to over 650 degrees C at
which point the isotopes Cs-133, Cs-135 and Cs-137 vaporize as the
oxides Cs2O, Cs2O2, Cs2O3 leaving behind U3O8 with some contaminant
Np. These vapors must be condensed in a cold trap. As indicated above
the contaminant Np is not a problem unless it contains Np-237 from
fast neutrons interacting with U-238.
4) During the initial
prebaking most of the trapped radioactive Kr-81, Kr-85 and Ar-39
inert gas atoms are released in the vacuum furnace. This trapped
inert gas mixture must be captured, condensed, stored, transported,
separated from Cs, adequately mixed with the atmosphere and safely
vented.
5) There must be a mechanism to safely prevent
uncontrolled release of any remaining inert gases or Cs while new UO2
is being added to the dissolver tank.
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CHEMISTRY:
U3O8
= UO2 + 2 UO3
UO2 + 2 HNO3 + 6 H2O = UO2(NO3)2.6H2O + H2 +
heat
UO3 + 2 HNO3 + 5 H2O = UO2(NO3)2.6H2O
UO2(NO3)2.6H2O +
heat = UO3 + 2 HNO3 + 5 H2O
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DEFINITIONS:
The
term "weak solution" refers to a UO2(NO3)2 4.5 M nitric
acid solution which is saturated at 20 degrees C. The term "strong
solution" refers to a UO2(NO3)2 4.5 M nitric acid solution which
is saturated at 100 degrees C.
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HYDRATION
OF UO2(NO3)2:
According to Wiki UO2(NO3)2.nH2O exists as a
dihydrate, a trihydrate and a hexahydrate. It appears that unless
concentrated nitric acid is used the result will be the hexahydrate.
However, when the hexahydrate is gradually heated during UO2 recovery
the hexahydrate may liberate water molecules to form the trihydrate
and then dihydrate forms.
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Typically in
real life a single stage of separation gives:
A ~ 0.95
and
B
~ 0.05
Recrystalization separation factor = (A / B) ~ 19
As (I / U) rises the rejection of impurities on crystal formation becomes less ideal. Impurities that chemically bond with the uranium nitrate hexahydrate are not rejected.
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P>RECRYSTALIZATION CASCADE DESCRIPTION:
The main
apparatus used for selective uranium oxide extraction is a nitric
acid dissolver followed by a seven stage uranyl nitrate hexahydrate
recrystallization tank cascade.
The mixed input to the cascade is
(Um + Im) where:
Um = uranyl nitrate hexahydrate solution
Im =
impurities (fission products and TRU)
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CASCADE
OVERVIEW:
In operation hot strong acid solution saturated with
UO2(NO3)2 at 100 degrees C is fed from the dissolver into tank T1a
and cool clean acid solution saturated with UO2(NO3)2.6H2O at 20
degrees C is later generated in tank T7a. As the dissolved used CANDU
fuel moves from tank column 1 to tank column 7 it converts from being
97.55% UO2(NO3)2.6H2O to being nearly pure UO2(NO3)2.6H2O. The
initial impurity fraction in used CANDU fuel is: 2.45% impurity to
about 24.5% impurity.
The equipment
consists of a dissolver, tanks Tnx where n = 1,2,3,4,5,6,7 and x =
a,b and two UO2 / acid recovery units. The dissolver contains
100degree C saturated solution with an excess of used CANDU fuel. The
system goes through a long series of temperature oscillations each
consisting of a slow cooling period from 80 degrees C down to 20
degrees C (320 minutes?) followed by a more rapid heating period from
20 degrees C back up to 80 degrees C (80 minutes?). After each
heating period clean hot solution is transferred one tank to the
right. During the subsequent cooling and crystal growth period TRUs +
FP are rejected from the crystals to the liquid. At the end of each
cooling period the remaining liquid solution flows down to tank Tnb
carrying the rejected impurities toward the impurity output. We can
refer to each complete module temperature oscillation as a
temperature cycle. Due to cleaner solution feedback the solution fed
back to tank Tna is cleaner than the solution that flowed into Tank
Tnb.
CASCADE
DESIGN:
The cascade is designed so that the various tanks
operate at progressively higher purities going to the right and at hi
impuity concentrations going downward. At the end of each heating or
cooling period acid solution is transferred from tank to tank nearly
sequentially. While liquid transfers are occurring the liquid volume
in the individual tanks fluctuates.
The tank temperatures are
programmed to oscillate, typically between 20 degrees C and 90
degrees C. The circulated heating oil reaches up to 120 degrees C for
warming and reaches down to 15 degrees C for cooling. Colder low end
temperatures are possible with a suitable mechanical cooling
equipment. The heating can be relatively fast (~ 1.0 degree C /
minute) but the cooling must be slow (~ 0.25 deg C / minute) and
carefully controlled. The required fine temperature control is
achieved by controlling the circulated oil temperature. During a tank
cooling periood UO2(NO3)2.6H2O crystals tend to grow on the textured
surfaces.
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INTERTANK
LIQUID TRANSFERS:
Intertank liquid transfers are realized by
applying air pressure over the source tank while venting the
receiving tank. When the vent tube of the receiving tank fills with
solution the liquid transfer is complete.
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TANK Tx TO TANK Ty SOLUTION TRANSFER SUBROUTINE:
A liquid transfer from
tank Tx to tank Ty is achieved by:
a) Stop solution agitation in
tank Tx;
b) Open the NO top vent valve on the top of tank Ty;
c) Open desired NC liquid discharge route valve branch off the discharge
tube of tank Tx;
d) Close the NO top vent valve on tank Tx;
e) Open the NC transfer air pressure valve on the top of tank Tx;
f) Wait for Tank Ty to indicate full or Tank Tx to indicate empty;
g) Close the NC transfer air
pressure valve on the top of tank Tx;
h) Open the air vent valve on tank Tx;
i) Close the NC liquid discharge route valve branch off
the teflon tube of tank Tx;
CASCADE FORMATION:
CASCADE OPERATION:
A cascade is
formed by connecting multiple crystal growing stages in series with residue feedback. Tanks
Tna, which each accommodate at least 2 U, oscillate in temperature. During a cooling period crystals form.
During a warming period crystals melt.
The normal operation initial condition is that each of tanks Tna contain 2 U (nearly full) of hot saturated solution and each of tanks Tnb contain (U / 10).
During the period during which tanks Tna are cooling solution amount (U / 10) is shifted left one position in tanks Tnb starting with T1b and moving to the right to T8b so that T8b is emptied. Tank T1b discharges (U / 10) to the cascade residue output. The amount (U / 10) is indicated by total discharge of each upstream tank into the next downstream tank as indicated by air in the liquid transfer circuit. The amount U / 10 is set by a measured amount that enters tank T8b.
Wait until all tanks Tna reach the desired low temperature (20 deg C). At the end of the cooling period all of the remaining cool liquid in each tank Tna (approximate volume U) is transferred to the accompanying tank Tnb. Note that tanks Tnb must each accommodate more than 1.1 U. This transfer occurs until each upstream tank Tna is dry as indicated by air in the common liquid transfer circuit.
Then tanks Tna and Tnb are both warmed. During a warming period the solid crystals in tanks Tna melt. Wait until all tanks reach the desired high temperature (100 deg C). Then moving from right to left the warm saturated solution of volume U is completely discharged to the next a tank T(n+1)a as indicated by air in the liquid transfer circuit. The volume (U /10) of the liquid discharged from the last tank Tna is discharged to tank T8b as indicated by a liquid level sensor in the T8b vent line and the then the remaining (9 U /10) is discharged to the UO2(NO3)2.6H2O cascade output. New saturated solution measured amount U flows from tank T0a (volume U) into tank T1a. In each case air in the common liquid transfer line indicates complete transfer. The volume in Toa is indicated by a liquid sensor in its vent line.
Then the warm liquid in tanks Tnb for n = 1 to 7 is transferred into tanks Tna where it is mixed with the newly shifted in liquid so that tanks Tna all contain 2 U. Completion of this liquid transfer is indicated by tank full sensors in the vent lines of tanks Tna.
Note that the liquid insertion amount U flowing from tank T0a and recirculated amount (U / 10) flowing from tank T8b are accurately calibrated.
CASCADE MATHEMATICS:
A practical
cascade design is one where recrystallization at each stage is
assumed to be imperfect. Assume that the weight of crystals = weight of solutution at the lowest temperature. Then the single stage transfer function is:
U + I = [(U / 2) + A I] + [(U / 2) + B I]
where cool output flow per thermal cycle is:
[(U / 2) + A I]
and where warm output flow per thermal cycle is:
[(U / 2) + B I]
where:
A + B = 1
U = total uranium nitrate hexahydrate stage input
I = total impurity stage input
CASCADE BOUNDARY CONDITIONS:
Cascade input = (U + I)
Cascade main discharge = (9 / 10)(U) + k (I)
For each Tnb stage:
Main output = 10 X Aux output
For tank T1b:
Main output = 10 [(1 / 10)(U) + (1 - k)(I)]
= (U) + 10 (1 - k) I
Cascade Separation Factor:
[(I / U)] / [k (I) /(U)]
= [1 / k]
FLOWS
FIRST STAGE ANALYSIS:
Tank T1a Main input = (U + I)
Tank T1a Aux input = 10[Residue discharge]
= 10 [(1 / 10)(U) + (1 - k)(I)]
= (U) + (1 - k) (10 I)
T1a total input = 2 U + (11 I) - k (10 I)
T1a warm output = (U) + B I[(11) - 10 k]
T1a cool output = (U) + A I [(11) - 10 k]
Tank T1b Main input = (U) + A I [(11) - 10 k]
Tank T1b Aux input = (U / 10) + K2 I
Tank T1b Total input = (11 U / 10) + A I [(11) - 10 k] + K2 I
Tank T1b Aux input = (Tank T1b total input - Tank T1b main input)
= (11 U / 10) + A I [(11 ) -10 k] + K2 I - [(U) + A I [(11) - 10 k]]
= (U / 10) + K2 I
K2 ~ (1)
Tank T1b Total input = Tank Tib total output
or
(11 U / 10) + A I [(11) - 10 k] + K2 I
= (11 U / 10) + (1 - k) 11 I
or
A I [(11) - 10 k] + K2 I = ( 1 - k) 11 I
or
A [(11) - 10 k] + K2 = (1 - k) (11)
or
K2 = (1 - k)(11) - A [(11) - 10 k]
= 11 (1 - k - A) + 10 k A
= 11 (B - k) + 10 k A
= 11 B - 11 k + 10 k A
= 11 B - k - 10 k + 10 k A
= 11 B - k - 10 k (1 - A)
= 11 B - k - 10 k B
For the
special case of many stages then:
k = 0:
giving:
K2 I = (11) I (1- A)
= (11 / 2) I B
which, as expected, is the same as the impurity carried forward via the T1a warm discharge.
The effective first stage separation factor is:
(I / U) / [B I ((11) - 10 k) / (U)]
= 1 / [B (11 - 10 k)]
which for k = 0 becomes:
1 / [B (11))]
= 1 / 11 B
which for B ~ (1 / 20) becomes:
20 / 11
LAST STAGE ANALYSIS:
Tank Ta Main Input = Tank Ta Total Input - Tank Ta Aux Input
= Tank Ta Total Output - Tank Ta Aux Input
= 2 U + I - [U + (10 / 11) A I + (B I/ 11)]
= U + I - (10 / 11) A I - (B I/ 11)]
Tank Ta Aux Input = Tank Tb main output
= U + (10 / 11) A I + (B I/ 11)
Tank Ta warm output = U + B I
Tank Ta cool output = U + A I
Tank Ta total output = 2 U = Tank Ta total input
Tank Tb Main Input = U + A I
Tank Tb Aux input = (U + B I) / 10
Tank Tb total input = (11 / 10) U + A I + (B I / 10)
Tank Tb Main Output = U + (10 / 11)[A I + (B I / 10)]
= U + (10 / 11) A I + (B I/ 11)
Tank Tb Aux output = (U / 10) + (A I / 11) + (B I / 110)
Last stage separation factor:
[I - (10 / 11) A I - (B I / 11)] / (B I)
= (1 / B) - (10 / 11)(A / B) - (1 / 11)
= (1 / B) - (10 / 11)((1 - B) / B) - (1 / 11)
= (1 / 11 B) + (9 / 11)
For B = (1 / 20):
Last stage separation factor = (29 / 11)
Thus 10 or
more stages, each with two tanks, may be required to reduce the
impurity concentration by a factor of 1000.
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FIRST STAGE
OVERVIEW:
In operation hot strong acid solution saturated with
UO2(NO3)2.6H2O at 100 degrees C is fed from the dissolver into tank
T1a main inlet. Tank T1a is then cooled to 20 degrees C. The
remaining cool liquid is transferred from tank row a to tank row b.
Thr remaining solid is then warmed. It converts from being 97.55%
UO2(NO3)2.6H2O to being nearly pure UO2(NO3)2.6H2O. The initial
impurity fraction in used CANDU fuel is: 2.45%.
The pure liquid is transferred from tank T1a to Tank T2a.
The contents of Tank T1b are heated and recycled back into tank T1a.
The contents of tank T0a are transferred into T1a.
Tank T1a then starts a new cooling cycle.
The contents of tank T1b should be heated to 100 degrees C before being transferred back into tank T1a.
Â
The impurity fraction at the cascade residue discharge is ~ 24.5%.
Â
SYSTEM
COMPONENTS:
The cascade is fed by a closed dissolver. The
dissolver has a heating coil and a removable fuel basket to enable
removal of undissolved fuel and zirconium hulls. In normal operation
the dissolver is always hot at 100 degrees C. The dissolver solution
is saturated by maintaining an excess of used CANDU fuel. The
dissolver receives HNO3 recovered from the two cascade outputs.
The cascade consists of a series of nitric acid resistant tanks designated by Tnx. n = 1, 2, 3, 4, 5, 6, 7 x = a, b The detail of the connections to tank T7x and T1b differs from the other tanks to enable the solution discharged by these tanks to feed the HNO3 recovery apparatus.
The tank discharge tubes are fed from the very bottom of each tank. The discharge connections to the adjacent downstream tanks are to the space above the liquid levels in the downstream tanks to ensure that there are liquid breaks in the connections between adjacent tanks. Each tank overhead gas space is vented to a common overhead vent pipe. This vent is sometimes closed to permit easy liquid transfer between tanks while safely containing hot HNO3 and related gases.
The tanks Tna are weakly agitated during crystal growth by circulating solution so that there is rising solution convection within the UO2(NO3)2.6H2O solution. The purpose of the weak agitation is to minimize impurity accumulation on the crystal faces during crystal growth and to prevent drain blockage by small crystals.
Each tank has temperature sensors which are used to regulate the heating/cooling rates and to indicate when a heating or cooling cycle is complete.
During the heating period the temperature of the oil is about 20 degrees C warmer than the temperature of the solution. During the cooling period the temperature of the oil is about 5 degees C cooler than the solution.
At the end of the heating and cooling periods the solution in each tank is transferrred into the next downstream tank.
Absent U-232 in the usedfuel this cascade should reduce the uranium oxide gamma emission per kg down to the level of new CANDU fuel formed from natural uranium_______??. The amount of U-232 gamma emission will be a strong function of the original Th-232 impurity concentration in CANDU fuel and a weak function of the age of the used CANDU fuel.
Â
FIXDuring an intertank solution transfer each transfer normally runs until there is no liquid in the upstream tank. The exceptions to this rule are for strong hot solution transfers from the dissolver into tank T1a. In these cases the solution transfer stops when the desired liquid level in tank T1a is attained.
The tanks all have liquid level overfill sensors.
There is
control logic which will stop the liquid transfer sequence and alarm
if any tank liquid level exceeds its design maximum. The floor under
the tanks is covered with an acid resistant stainless steel sheet and
is sloped to a common drain. The drain goes to the basement level
dirty acid drain down tank. Thus any acid leak anywhere in the system
gravity drains into this dirty acid drain down tank.
CASCADE
MAINTENANCE:
To enable system maintenance the dissolver basket
containing remaining fuel and zirconium hulls is removed and placed
behind a shielded barrier, all the tanks are heated to 100 degrees C
to fully dissolve the remaining solids and then the entire system
solution volume is drained down into the shielded below grade acid
drain down tanks. Below the drain down tanks are pumps which can be
used to transfer the acid solution back into the cascade after the
service work is complete.
The cascade
requires drain and rinse valves to enable cascade draining and
flushing.
  SYSTEM OPERATION: The equipment consists of a dissolver, 28 tanks Tnx where n = 1,2,3,4,5,6,7 and x = a,b,c and two UO2 / acid recovery units. The dissolver contains impurities at the equilibrium concentration in the used CANDU fuel. The system goes through a long series of temperature oscillations each consisting of a slow cooling period from 80 degrees C down to 20 degrees C (320 minutes?) followed by a more rapid heating period from 20 degrees C back up to 80 degrees C (80 minutes?). After each heating period hot solution is transferred down one tank. During the subsequent cooling and crystal growth period TRUs + FP are rejected from the crystals to the solution. At the end of each cooling period the remaining liquid solution flows forward one tank to the right carrying the rejected impurities toward the impurity output. We can refer to each complete module temperature oscillation as a temperature cycle.
OPERATION:
The tanks oscillate in temperature. The cascade operates by taking
advantage of the temperature dependence of UO2(NO3)2 solubility in
4.5 M HNO3. Lowering the temperature of a saturated solution triggers
recrystallization. During slow recrystallization impurity atoms are
excluded from the UO2(NO3)2.6H2O crystals and concentrate in the
surrounding liquid. In order to realize high purity UO2(NO3)2.6H2O a
cascade containing multiple successive recrystalization steps is
used. Â While a tank is being heated or cooled there is
no solution flow in or out of that tank. After a cooling period there
is a cool solution discharge period. After a warming period there is
a warm solution discharge period. During the cooling period crystals
form which increase the residue concentration in the liquid
surrounding the crystals. At the end of the cooling period crystals
containing nearly pure uranium nitrate hexahydrate are retained by a
screen and the surrounding cool liquid is transferred one tank
position toward the residue discharge. Then the tank is heated. The
UO2(NO3)2.6H2O crystals in tanks re-dissolve in the cleaner
surrounding warm acid solution. The solution resulting from melting
the remaining crystals in tank T7x is transferred into the UO2 / HNO3
recovery system. Â Then there is a warming period during
which the crystals melt. Then the warm liquid flows one tank position
downward toward the nearly pure uranium discharge. Then the tank is
reloaded from its two upstream tanks. Then another cooling period
commences. Â During steady state operation the fraction:
(TRU + FP) / U at the cascade residue discharge builds up to be about
10X the (TRU + FP) / U fraction in the used CANDU fuel, which
fraction is several orders of magnitude higher than the corresponding
value of (TRU + FP) / U at the nearly pure uranium oxide discharge.
There are seven_____ columns of tanks in four rows designated n = 1, 2, 3,
4, 5, 6,7 and x = a, b. The tank at column n, row x is Tnx. The
seven_____ columns and two rows are required to hit two targets. As
uranyl nitrate hexahydrate moves from column 1 to column 7____ the ratio of I /
U in the nearly pure uranium output must drop at least 1000 fold. As
uranyl nitrate hexahydrate moves from row a to row b the ratio
of I / U in the FNR fuel feedstock must increase at least 10 fold. The used CANDU fuel is dissolved in warm HNO3. Then on row a the Nth
tank of the cascade behaves as follows: PROCESS
ECONOMICS: With careful
adjustment one system will process UO2 at 83 kg / day
yielding a TRU output of The ultimate
value of fissile is $7600 / kg Thus the gross
value of this fissile fuel after pyroprocessing is: Assume that
the TRU concentration apparatus costs $500,000 and needs to earn a 2
year simple payback on capital plus $100,000 / year for cost of
operation. Gross income
is $2523 / day X 365 days / year = $920,968 year. Hence,TRU
concentration costs $350,000 / year leaving: One CANDU
reactor produces 4 g TRU / kg UO2 X 100,000 kg UO2 / 1.5 years = 267
kg TRU / year One TRU
concentrator produces: Need 2 systems
at $500,000 each to balance one CANDU reactor. Â
a) Transfer uranium nitrate
hexahydrate solution from two upstream tanks to tank Tna until both
upstream tanks are empty;
b) Cool tank Tna to form uranyl nitrate
hexahydrate crystals + excess solution. The crystals must form about
half the total weight.
c) Transfer the remaining cool liquid from
tank Tna to tank Tnb until there is no more liquid in Tank Tna;
d) Warm tank Tna to melt the crystals remaining in tank Tna;
e) Transfer the entire warm solution from tank Tna to tank T(n+1)a.
f) Repeat the above sequence subject to readiness of both upstream and
down stream tanks. Total mass flow into tank T1a is (U + I) where U =
uranium nitrate hexahydrate and I = impurity Cold liquid discharge
from top of T1a is (U / 2) + A I Hot liquid discharge from main output
of T1a is (U / 2) + B I A + B = 1.000
Due to crystal exclusion of
impurity I material and careful mechanical design: A ~ 0.99 B ~ 0.01
Note that A and B must be experimentally determined. With reference
to the diagram:
__________ indicating that the impurity concentration in the UO2 is
reduced more than 100 fold. Thus a separation factor of 19 gives an
impurity enhancement of 10 fold and and impurity reduction of more
than 100 fold in UO2. Recall that: A + B = 1 and Separation factor =
(A / B) ~ 19 Calculation check: B = (1 - A) B^2 = (1 -2 A + A^2) B^3
= (1 - 2A + A^2 - A + 2 A^2 - A^3) = (1 - 3A + 3 A^2 - A^3) Substitue
for B in the above equations and check that the sum of the total
outputs = (U + I). Â SOLID RECOVERY: The U + Pu + Fp
impurities are harvested from the liquid solution in the dissolver
after the dissolver has reached its equilibrium impurity
concentration. The extracted dissolver solution is heated to
evaporate the nitric acid which is recovered and recycled. A
significant amount of energy is required. The resulting dry residue
is the feedstock for successive operations to make FNR core fuel.
Very strong UO2(NO3)2.nH2O from tank T5 is transferred to the UO2
/acid recovery unit. Heating this very strong solution to recover the
UO2 and the contained acid and the cesium oxide compounds requires a
substantial amount of energy. The very strong solution in the UO2
/acid recovery unit is mildly heated to drive off the nitric acid
which is recycled. The dry residue is then heated to 650 degrees C to
drive off radioactive cesium oxides which are caught in a cold trap
and sent to 300 year storage. The remaining high purity depleted
uranium oxide has a very low radioactivity and should be stored for
future use as FNR blanket rod material. Â Note that over
time the quantity of Zr hulls in the dissolver will gradually
increase. From time to time the process must be stopped to allow Zr
extraction. Â SOLUBIlITY: 0 deg C = 98 g / 100 g H2O 20
deg C = 122 g / 100 g H2O 100 deg C = 474 g / 100 g H2O Solute mass
per 100 g H2O that moves one tank forward with each thermal cycle:
(474 g - 122 g) / 100 g = 352 g UO2(NO3)2 / 100 g H2O Solute mass per
100 g H2O that moves two tanks backward with each thermal cycle: =
122 g / 100 g H2O Net solute that moves forward one tank in one
thermal cycle is: 352 g / 100 g H2O - 2(122 g / 100 g H2O) =Â 108
g / 100 g H2O The amount of CANDU fuel processed per thermal cycle
is: [UO2 / UO2(NO3)2] X 108 g / 100 g H2O = [(238 + 32) / (238 + 32 +
2 (14 + 48))] X 108 g / 100 g H2O = [(270) / (270 + 124)] X 108 g /
100 g H2O =Â 74.01 g / 100 g H2O Mass per tank per 100 g
H2O that must be heated and cooled in each thermal cycle is: 100 g
H2O + 474 g UO2(NO3)2 Â TANK VOLUMES: The volume of a
basement drain down tank sufficient to absorb the entire volume in
the dissolver, Tnx is: ________ We may need to be concerned about
accumulating a critical mass in the dissolver. Hence, we may need to
rethink these tank sizes. Note that the submerged tube surface area
must be consistent with the assumed heat transfer rate. Â
HEAT REQUIRED TO DRIVE ONE THERMAL CYCLE OF OPERATION:
____________________ Estimate the heat required to swing all 21 tanks
through 105 degrees C: _________ 5 tanks X 574 g / stage/ 100 g H2O X
80 deg C X 1 cal / g-deg C X 4.18 J / cal = 959,728 J / 100 g H2O =
959,728 J / 100 g H2O X 1 W-s / J X 1 kWt / 1000 W X 1 h / 3600 s
=Â 0.2666 kWht / 100 g H2O Note that this figure does not
include the heat capacity of the tank metal. Heat of formation of
UO2(NO3)2.6H2O: = -2739.5 Btu/lb of UO2(NO3)2 This is the heat that
must be supplied to release UO2 from UO2(NO3)2.6H2O crystals. 1 Btu =
heat required to raise 1 lb of H2O 1 deg F = heat required to raise
454 g of H2O (1 / 1.8) deg C = heat required to raise 252.2 g of H2O
1 deg C = 252.2 cal 1 lb = 454 g Hence: (1 Btu / lb) = 252.2 cal /
454 g = 0.5555 cal / g Thus the heat required to recover UO2 from
UO2(NO3)2.6H2O is: 2739.5 Btu/lb of UO2(NO3)2 =2739.5 Btu/lb X
(0.5555 cal / g) / (1 Btu / lb) = 1522 cal / g of UO2(NO3)2.6H2O Each
thermal cycle produces 108 g of UO2(NO3)2.6H2O. Thus the heat
required for UO2 recovery per thermal cycle is: 108 g X 1522 cal / g
= 164,376 cal = 164,376 cal X 4.18 J / cal = 687,092 J = 687,092 J X
1 W-s / J X 1 kWt / 1000 W X 1 h / 3600 s =Â 0.1908 kWht
Thus the energy required per thermal cycle / 100 g H2O / tank is:
0.1908 kWht + 0.2666 kWht =Â 0.45746 kWht / 100 g H2O /
tank From above, each thermal cycle produces: 74.01 g UO2 / 100 g H2O
Thus at a minimum a facility processing 5000 kg / day of used CANDU
fuel has an average thermal power consumption of: 5000 kg / day X 1
day / 24 h X 0.47546 kWht/74.01 g X 1000 g / kg =Â 1338.38
kWt By the time fan and pump loads for heat removal are added and the
heat capacity of the tanks is included this will be about 2.0 MWt.
Note that this is an average heating power. In reality the system
heats for 80 minutes followed by a cooling period of 320 minutes.
Thus during the heating periods the peak power is 5X the average or:
5 X 2 MWt =Â 10 MWt. Note that the UO2 / HNO3 recovery
unit can be run continuously. Hence about 800 kWt is needed
continuously and about 6 MWt are needed with a 20% duty cycle. Â
SOLVE FOR ACTUAL HEATING AND COOLING TIMES TANK REQUIREMENT: Each
temperature cycle = 400 minutes. Number of temperature cycles per day
= [24 h X 60 m / h] / [400 min / cycle] = 3.6 cycles / day In order
to produce 5000 kg / day of UO2, each cycle must produce: 5000 kg /
3.6 = 1389 kg UO2 Each 100 g of acid produces: 74.01 g UO2. Hence the
required number of 100 g units of acid per tank is: 1389 kg / 74.01 g
= 18.77 X 10^3 Hence the required amount of acid / tank is: 18.77 X
10^3 X 100 g = 1877 kg Hence it appears that the estimated tank
volumes are 2 X larger than necessary. However, that extra volume
allows for the tube and manifold volume in a shell and tube heat
excahnge configuration with water-glycol in the tubes and volume
expanding crystals on the shell side. Wrapped around the outside of
the vertical tubes must be a perforated sheet to stop crystals
falling into the shell side drain. Â MECHANICAL USED
CANDU FUEL FEED: a) From the used CANDU fuel inventory that has been
out of a CANDU reactor for at least 10 years withdraw used CANDU fuel
bundles as required. b) Mechanically shear the used CANDU fuel
bundles into small pieces, each about 3 cm long. c) Feed these pieces
into the dissolver at a controlled rate sufficient to keep the
dissolver solution saturated at 100 degrees C. Â
ZIRCONIUM RECOVERY: Over sufficient time the dissolver will fill up
with Zr hulls and must be stopped to remove these hulls. The
dissolver contains a large basket to expedite Zr hull recovery. Â
DISSOLVER OPERATION: a) The dissolver is a nitric acid resistant tank
with a removeable top. The dissolver tank contains a nitric acid
resistant basket to allow convenient zirconium hull recovery. An
empty basket is lowered into the dry dissolver tank, the dissolver
tank top is replaced and the dissolver tank is evacuated. This
evacuated air is exhausted to the atmosphere. The evacuation valve is
then closed. b) Then hot nitric acid temporarily stored in the drain
down tank is pumped into the dissolver. c) Due to the low overhead
pressure in the dissolver tank nitric acid containing a low UO2(NO3)2
concentration flows from the drain down tank into the dissolver where
it is heated to 100 degrees C. Used CANDU fuel is added to the
dissolver via a feed tube. After some time in the nitric acid at 100
degrees C in the dissolver solution becomes saturated with UO2(NO3)2.
Undissolved zirconium pieces collect in the dissolver's bottom
basket. Radioactive inert gas fission products such as krypton bubble
up through the liquid acid and collect in the sealed space above the
acid. d) Then a controlled volume of the hot nitric acid solution is
pumped from the dissolver tank into tank T1 via the port at the
bottom of the dissolver. Sufficient nitric acid solution remains in
the dissolver tank over this port to prevent the radioactive inert
gas fission products on top of the dissolver solution from exiting
the dissolver via its bottom port. e) Eventually when the inert gas
pressure over the acid in the dissolver tank becomes too high or when
the dissolver tank full of Zr hulls the dissolver is cooled to 20
degrees C to reduce the partial pressure of remaining HNO3 gas in the
dissolver head space. f) The inert gas plus some HNO3 gas in the
dissolver head space are evacuated via a cold trap. The HNO3 vapor is
caught in the cold trap. The radioactive inert gases are sent either
to a high stack or to a pressure tank for later safe release to the
atmosphere at a remote location. Ideally the inert gas should be
stored to allow it to naturally decay. After a suitable decay period
vent the residual inert gas to the atmosphere. Note that radioactive
Kr-81, Kr-85 and Ar-39 must be well mixed with the atmosphere. g) The
nitric acid in the cold trap is isolated and is recycled back to the
disssolver. h) When the dissolver is full of Zr hulls the dissolver
is drained into the drain down tank. i) The dissolver tank top is
removed. The basket containing zirconium pieces is removed from the
dissolver and is air dried. The neutron activated zirconium is
harvested from the dissolver basket for future use as a component of
FNR fuel. j) Transport the neutron activated zirconium and the CANDU
fuel concentrates to the remote irradiated zirconium and fuel stores.
k) The now empty dissolver tank basket is replaced and the dissolver
batch cycle repeats. Note that the dissolver tank is sufficiently
large that one dissolver batch will serve many temperature cycles.
Note that as the system operates the amount of UO2 in the dissolver
gradually diminishes but the acid liquid level in all the tanks
remains almost constant and the UO2(NO3)2 concentration in the
dissolver solution remains almost constant. From time to time new
used CANDU fuel is added via the feed tube. Â
MISCELLANEOUS CASCADE ISSUES: 4) Provide perforated sheet cylinders
in each tank to provide crystal growth surfaces and to prevent
crystals being sucked into the inlet of a backward pump. These must
be perforated all the way to their bottom edges to ensure complete
drainage. 5) It is necessary to carefully control the liquid
transfers to realize the optimum acid volume in each tank at a
particular time in the operating cycle. If there is too much acid in
a tank the system will be energy inefficient on thermal cycling and
the forward solute propagation will be poor. If there is too little
acid in a tank not all the crystals will be dissolved during a tank
heating cycle, leading to insufficient crystal growth in the next
tank during its cooling cycle. Thus the liquid levels must be
carefully controlled. Each tank should have a precise liquid level
sensing device and a pressure sensor at the tank discharge. The level
control in tank T1 is particularly important as it sets the levels in
the other tanks if the tank flows are all properly balanced. Thus the
tube sheets and end manifolds must have provisions for the required
shell side liquid level sensors. Â UO2 RECOVERY AND ACID
RECOVERY 1) Chop up the used fuel bundles. 2) Move the [U3O8 +
contamination Cs2O,Cs2O2, Cs2O3] from #1 above to a suitable furnace.
3) Heat the [U3O8 + contamination Cs2O,Cs2O2, Cs2O3] residue above
650 C to drive off the Cs2O, Cs2O2, Cs2O3 as a condensable gas. 4)
Condense and collect the radioactive Cs2O, Cs2O2, Cs2O3. 5) Send the
radioactive Cs2O, Cs2O2, Cs2O3 to fission product 300 year storage.
After 30 years in storage the radioactivity should be dominated by
Cs-137 (30 year half life) and Cs-135 (3.0 X 10^6 year half life).
Use a segragated store in case this material contains other
contaminants. 6) The remaining solution dry residue is CANDU fuel
concentrates for further reprocessing (fission products + TRUs +
uranium oxide). 7) Apply the cascade. 8) Heat the cascade discharge
products to evaporate, condense, recover and recycle the HNO3. 8)
Transport the CANDU fuel concentrates (fission products + TRUs +
uranium oxide) to the remote site for electrolytic reprocessing. Â
MINIMIZASTION OF CANDU FUEL REPROCESSING COST: 1) The purification of
U is not a matter of choice. The subsequent pyroprocess has to
extract enough U in total first so that the cadmium cathode can start
working on the transuranics. Otherwise it extracts the U into the
molten Cd until the transuranics start coming out. That step is done
cleaner on the iron cathode. It just happens that the iron cathode
produces pure U as it extracts it without the transuranics. 2) To
make the overall process as inexpensive and short as possible, the
pre-extraction of U should ideally go to as high a percentage of U as
possible without introducing unacceptable levels of impurities. Â
SYSTEM SERVICE: The envisaged cascade is orders of magnitude more
mechanically simple than the earlier student design summarized below.
From time to time the system will likely need mechanical service. To
safely enable such service both the HNO3 and the radioactive species
must be completely drained. To service the system heat the entire
system to 100 degrees C to dissolve all of the UO2(NO3)2. Lift out
the dissolver basket with a gantry crane and place it in a shielded
enclosure and then drain all the fluids from the drain valves below
the bottoms of the tanks to shielded below grade drain down tanks. If
the radiation from residue remaining in the system is too high flush
the system with clean 4.5 M nitric acid. Â UO2(NO3)2
DATA: MP = 60.2 deg C Dissociation at 118 deg C UO2(NO3)2 is
hygroscopic forming 6(H2O), 3(H2O), 2(H2O) TOXICITY OF UO2(NO3)2: 12
mg / kg (dog) Natural Uranium: U-238 99.27%, 4.47 X 10^9 Y U-235
0.711% 700 X 10^6 Y U-234 ~ 0.019% Price of uranium oxide ~ $28 / lb
 MECHANICAL DESIGN: One of the important design
constraints is set by tube sheet flexing. During the heating period
the heat exchange tubes are about 20 degrees C hotter than the shell
wall. During the cooling period the tubes are about 5 degrees C
cooler than the shell wall. Hence even if the tubes and shell wall
are perfectly TCE matched the tube sheets will still flex back and
forth with each temperature cycle. Hence the heat exchange tubes must
be centrally located in the tube sheets and the width of the
non-tubed ring around them in combination with the tube sheet
material thickness must accommodate continuous tube sheet flexing.
Thus the tank height, the temperature coefficient of expansion, the
Young's modulus, the yield stress, the tube wall thickness and the
shell wall thickness will all be important. Keeping the tubes
centrally located will reduce the heat transfer area. In order to
move this design forward we need the physical properties of the
material, which will be determined in part by the corrosion
resistance. It may prove necesssary to make the top tube sheet
thinner than the bottom tube sheet which must support the fluid head.
 CASCADE MATERIAL SELECTION: Peter Ottensmeyer: The only
plastic that is HNO3 resistant is Teflon (PTFE). WHAT ABOUT EPOXYS?
The preferred materials are 440 stainless steel, ceramic, and
titanium  John Rudesill: The concept Charles has
described has merit. Counter current separations are ideally more
efficient than single stage separations and are a preferred design
practice in chemical engineering when practical. The link I sent to
Charles earlier
https://www.rolledalloys.com/technical-resources/environments/nitric-acid/
indicates that various SS alloys are used in contact with 60% HNO3 at
temperatures well in excess of 110 C. Plastic could work, but is both
structurally and thermally inferior to SS alloys, The heat conduction
coefficient is also much lower than metals. I will dig a little
deeper for approved metals for this service. We have to be aware that
the FP's contain halides which can make HNO3 far more corrosive. I
need to see the expected solution analysis of the product coming from
the fuel element dissolution step to account for the halide content.
I am aware than jacketed tanks are made of even carbon steel and
lined with teflon to make them near impervious to corrosion until the
eventual pin hole forms leading to liner failure and jacket
penetration. Heat transfer is impeded, but is still workable. Teflon
can be used over 200 C as long as it is not used in a structural
role. Similarly metal tubing can be teflon coated. For some services
polyvinyl difluoride (F analog of Saran) can be used in place of
teflon and it is somewhat more structurally robust. I will read over
the procedure Charles has provided and see if I can make a hand
sketch of this process to study. It makes sense to scope this concept
out at the kg/d scale or even smaller before making any commitments
to a detailed design for a ~5mt/d facility. Materials handling will
be a dominant aspect of the design given the radio hazard content. A
5 mt /d process rate may seem like a lot, but is a very modest pilot
plant. There is little incentive to try to save on equipment costs as
they will be at large variance with usual engineering economy of
scale cost calculations. The design must prioritize absolute
containment and separation completeness over almost all other
considerations. We want to do each step only once--no do overs at
least in a continuous flow mode. In a batch mode, a step can be
repeated if necessary. Also, batch mode can enable single shift 5 day
week operation, initially. Continuous operation must be 24/7. As I
write this, I think batch mode is the wiser choice. Once it is up and
running and understood, a prudent consideration of continuous 24/7
operation is reasonable. Â
Assume that we can process 14,000 ml of solution
per temperature cycle. That is a solution mass of:
(2.2 kg / 1000
ml) X 14,000 ml / cycle = 30.8 kg / cycle.
The weight of uranyl
nitrate hexahydrate UO2(NO3)2.6H2O processed per cycle is:
[(2.8 X
0.66) / 2.2] X 30.8 kg / cycle = 25.872 kg / cycle
Assume 6
temperature cycles per day:
6 cycles / day X 25.872 kg / cycle =
155.23 kg / day uranyl nitrate hexahydrate
Weight Fraction UO2 =
UO2 / [UO2(NO3)2.6H2O]
= (238 + 32) / [238 + 32 + 2(62) + 6(18)]
=
270 / [270 + 124 + 108]
= 270 / 502
= 0.5378
Hence UO2
throughput = 155.23 kg /day X 0.5378
= 83.483 kg /day
83 kg / day X 4 g / kg = 332 g / day TRU.
0.332 kg/ day
X $7600 / kg = $2523 / day
which must include the cost of
pyroprocessing.
920,868 - 350,000 =
$570,560 / year
for pyroprocessing 332 gm / day TRU or 1.66 kg /
day of FNR core fuel.
0.332 kg TRU / day X 365 day / year = 121
kg / year
Thus we need 2.2 TRU concentrators for every CANDU
reactor.
This web page last updated December 30, 2020